Given two independent events A and B such that P(A) =0.3, P(B) = 0.6 and P(A’∩ B’) is

These are the options for the question : Given two independent events A and B such that P(A) =0.3, P(B) = 0.6 and P(A’∩ B’) is

(a) 0.9           (b) 0.18        (c) 0.28          (d) 0.1

The correct answer is -(c) P(A’∩ B’) = 𝑃(𝐴′) × 𝑃(𝐵′) (As A and B are independent, A’𝑎𝑛𝑑 B’ are also independent.)
= 0.7 × 0.4 = 0.28