{"id":133949,"date":"2023-03-12T16:57:05","date_gmt":"2023-03-12T11:27:05","guid":{"rendered":"https:\/\/www.mapsofindia.com\/my-india\/?p=133949"},"modified":"2023-03-12T16:57:05","modified_gmt":"2023-03-12T11:27:05","slug":"find-the-coordinates-of-the-foot-of-the-perpendicular-drawn-from-point-573-to-the-line-x-15-3-y-29-8-z-5-5","status":"publish","type":"post","link":"https:\/\/www.mapsofindia.com\/my-india\/quiz\/find-the-coordinates-of-the-foot-of-the-perpendicular-drawn-from-point-573-to-the-line-x-15-3-y-29-8-z-5-5","title":{"rendered":"find the coordinates of the foot of the perpendicular drawn from point (5,7,3) to the line x-15\/3= y-29\/8= z-5\/-5"},"content":{"rendered":"<h2>Question: find the coordinates of the foot of the perpendicular drawn from point (5,7,3) to the line x-15\/3= y-29\/8= z-5\/-5<\/h2>\n<p>&nbsp;<\/p>\n<h3>The correct answer is &#8211;<\/h3>\n<div class=\"flex-1 overflow-hidden\">\n<div class=\"react-scroll-to-bottom--css-gletb-79elbk h-full dark:bg-gray-800\">\n<div class=\"react-scroll-to-bottom--css-gletb-1n7m0yu\">\n<div class=\"flex flex-col items-center text-sm dark:bg-gray-800\">\n<div class=\"group w-full text-gray-800 dark:text-gray-100 border-b border-black\/10 dark:border-gray-900\/50 bg-gray-50 dark:bg-[#444654]\">\n<div class=\"text-base gap-4 md:gap-6 md:max-w-2xl lg:max-w-2xl xl:max-w-3xl p-4 md:py-6 flex lg:px-0 m-auto\">\n<div class=\"relative flex w-[calc(100%-50px)] flex-col gap-1 md:gap-3 lg:w-[calc(100%-115px)]\">\n<div class=\"flex flex-grow flex-col gap-3\">\n<div class=\"min-h-[20px] flex flex-col items-start gap-4 whitespace-pre-wrap\">\n<div class=\"markdown prose w-full break-words dark:prose-invert light\">\n<h4>To find the foot of the perpendicular drawn from point (5,7,3) to the given line, we need to first find a point on the line and the direction vector of the line.<\/h4>\n<h4>The direction vector of the line is given by the coefficients of x, y, and z in the line equation. Therefore, the direction vector of the line is (3, 8, -5).<\/h4>\n<h4>Let (a, b, c) be a point on the line. Then, we have:<\/h4>\n<h4>(a &#8211; 15)\/3 = (b &#8211; 29)\/8 = (c &#8211; 5)\/(-5)<\/h4>\n<h4>Solving for a, b, and c, we get:<\/h4>\n<h4>a = 15 + 3t b = 29 + 8t c = 5 &#8211; 5t<\/h4>\n<h4>where t is a parameter.<\/h4>\n<h4>Now, let&#8217;s find the equation of the plane passing through the given point (5,7,3) and perpendicular to the line. The normal vector of the plane is the direction vector of the line. Therefore, the equation of the plane is given by:<\/h4>\n<h4>3(x &#8211; 5) + 8(y &#8211; 7) &#8211; 5(z &#8211; 3) = 0<\/h4>\n<h4>Simplifying the equation, we get:<\/h4>\n<h4>3x + 8y &#8211; 5z = 94<\/h4>\n<h4>Now, let&#8217;s find the intersection of the line and the plane. Substituting the parametric equations of the line into the equation of the plane, we get:<\/h4>\n<h4>3(15 + 3t) + 8(29 + 8t) &#8211; 5(5 &#8211; 5t) = 94<\/h4>\n<h4>Simplifying the equation, we get:<\/h4>\n<h4>89t = -6<\/h4>\n<h4>Therefore, t = -6\/89.<\/h4>\n<h4>Substituting t into the parametric equations of the line, we get:<\/h4>\n<h4>a = 15 + 3(-6\/89) = 129\/89 b = 29 + 8(-6\/89) = 191\/89 c = 5 &#8211; 5(-6\/89) = 299\/89<\/h4>\n<h4>Therefore, the foot of the perpendicular from point (5,7,3) to the line is (129\/89, 191\/89, 299\/89).<\/h4>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Question: find the coordinates of the foot of the perpendicular drawn from point (5,7,3) to the line x-15\/3= y-29\/8= z-5\/-5 &nbsp; The correct answer is &#8211; To find the foot of the perpendicular drawn from point (5,7,3) to the given line, we need to first find a point on the line and the direction vector [&hellip;]<\/p>\n","protected":false},"author":21842,"featured_media":132233,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12119],"tags":[],"class_list":{"0":"post-133949","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-quiz"},"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/posts\/133949","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/users\/21842"}],"replies":[{"embeddable":true,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/comments?post=133949"}],"version-history":[{"count":1,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/posts\/133949\/revisions"}],"predecessor-version":[{"id":133950,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/posts\/133949\/revisions\/133950"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/media\/132233"}],"wp:attachment":[{"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/media?parent=133949"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/categories?post=133949"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.mapsofindia.com\/my-india\/wp-json\/wp\/v2\/tags?post=133949"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}