How long can an electric lamp of 100 W be kept glowing by fusion of 2 kg of deuterium? Take the fusion reaction as
ANS 6 Number of atoms present in 2 g of deuterium = 6 × 10ଶଷ
Number of atoms present in 2.0 Kg of deuterium = 6 × 10ଶ
Energy released in fusion of 2 deuterium atoms
= 3.27 MeV Energy released in fusion of 2.0 Kg of deuterium atoms
