Home Quiz Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively.

Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively.

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Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively.

Question :Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively.

The correct answer :Let the first term of the AP be a and the common difference be d. Then, the second term is a + d, and the third term is a + 2d.

According to the problem, we have:

a + d = 14 (1) a + 2d = 18 (2)

Subtracting equation (1) from equation (2), we get:

d = 4

Substituting this value of d into equation (1), we get:

a + 4 = 14

a = 10

Therefore, the AP is: 10, 14, 18, 22, …

The sum of the first n terms of an AP is given by the formula:

S_n = n/2 [2a + (n-1)d]

Substituting a = 10, d = 4, and n = 51, we get:

S_51 = 51/2 [2(10) + (51-1)4] = 51/2 [20 + 200] = 51/2 x 220 = 5625

Therefore, the sum of the first 51 terms of the AP is 5625.