Quiz Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively. Rohit Sharma - March 21, 2023 0 Question :Find the sum of first 51 terms of an A.P. whose second and third terms are 14 and 18, respectively. The correct answer :Let the first term of the AP be a and the common difference be d. Then, the second term is a + d, and the third term is a + 2d. According to the problem, we have: a + d = 14 (1) a + 2d = 18 (2) Subtracting equation (1) from equation (2), we get: d = 4 Substituting this value of d into equation (1), we get: a + 4 = 14 a = 10 Therefore, the AP is: 10, 14, 18, 22, … The sum of the first n terms of an AP is given by the formula: S_n = n/2 [2a + (n-1)d] Substituting a = 10, d = 4, and n = 51, we get: S_51 = 51/2 [2(10) + (51-1)4] = 51/2 [20 + 200] = 51/2 x 220 = 5625 Therefore, the sum of the first 51 terms of the AP is 5625.